Poker probabilities









 

 


We are playing poker with a standard deck of cards consisting of 52 cards. A starting hand consists of 5 cards.

How many different starting hands can you get?

\[\dbinom{n}{k} = \frac {n!}{k!(n-k)!} = \dbinom{52}{5} = \frac {5!}{5!(52-5)!} = 2,598,960\]



choose(52, 5)


[1] 2598960




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